(2x+3)^2=4x+69

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Solution for (2x+3)^2=4x+69 equation: 



(2x+3)^2=4x+69

We move all terms to the left:

(2x+3)^2-(4x+69)=0

We get rid of parentheses

(2x+3)^2-4x-69=0

We add all the numbers together, and all the variables

-4x+(2x+3)^2-69=0

We move all terms containing x to the left, all other terms to the right

-4x+(2x+3)^2=69

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